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Laws Of Motion

Question
CBSEENPH11017035

A force acts for 8 seconds on a body of mass 10 kg. The force then stops acting and the body describes 80 m in next 5 sec. Find the force. 

Solution

Here, 
Mass, m = 10 kg; t = 8 sec 
After the force stops acting, the body moves with a uniform velocity given by, 
v = fraction numerator distance space travelled over denominator time space taken end fraction space equals space 80 over 5 space equals space 16 space m divided by s
Initial velocity of the body, u = 0 
Using equation of motion, 
v = u + at 
16 = 0 + a x 8
a = 2 m/s2 
Therefore, 
Force, F = ma = 10 cross times space 2 = 20 N