-->

Laws Of Motion

Question
CBSEENPH11017034

Two bodies of masses 11 kg and 11.5 kg are connected by a long string passing over a smooth pulley. Calculate the velocity and height ascended/ descended by each body at the end of 4s. 

Solution

Given here, 
m1 = 11 kg; m2 = 11.5 kg 
Therefore, 
Acceleration comma space straight a space equals space fraction numerator left parenthesis straight m subscript 2 space minus space straight m subscript 1 right parenthesis space straight g over denominator straight m subscript 2 space plus space straight m subscript 1 end fraction space

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator left parenthesis 11.5 space space minus 11 right parenthesis over denominator left parenthesis 11.5 space plus 11 right parenthesis end fraction 9.8

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 4.9 over denominator 22.5 end fraction space equals space 0.218 space straight m divided by straight s squared

Using space the space relation comma

space straight v space equals space straight u space plus at

space space space space equals space 0 plus space.0218 space straight x 4 space equals space 0.872 space straight m divided by straight s

Again comma space using space the space relation comma space

straight s space equals space ut space plus space 1 divided by 2 space at squared

space space space equals space 0 space plus space 1 divided by 2 space straight x 0.218 space left parenthesis 4 right parenthesis squared space

space space space equals space space 1.744 space straight m

space space space space space space space space space space space space space space