Question
A body of mass m lying on a frictionless table has a light inextensible string attached to it. The string passes through a hole on the surface of table and has a body of mass M suspended from its other end. The system is kept in equilibrium by revolving the body on the table in a circle of radius r. Find the speed of the body to keep the system in equilibrium.
Solution
Let v be the speed of mass m.
As the svstem is in equilibrium, therefore
T = Mg ...(1)
and
...(2)
From (1) and (2),
So,
, is the required speed of the body to be in equilibrium.
As the svstem is in equilibrium, therefore
T = Mg ...(1)
and
...(2)From (1) and (2),
So,
, is the required speed of the body to be in equilibrium.
