At what angle the circular railway track of radius 200 m must be banked for speed 72 km/hr?

Solution

Given,
Radius of the circular railway track, r = 200m
Speed of the train, $v equals 72 space k m divided by h r space equals space 20 space m divided by s$
We know, the angle of banking is,
$straight theta equals tan to the power of negative 1 end exponent open parentheses fraction numerator v squared over denominator r g end fraction close parentheses$
$rightwards double arrow$ $space space straight theta equals tan to the power of negative 1 end exponent open parentheses fraction numerator left parenthesis 20 right parenthesis squared over denominator 200 cross times 9.8 end fraction close parentheses equals 11 degree 32 apostrophe$ , is the angle of banking.

Some More Questions From Laws of Motion Chapter

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Laws Of Motion

At what angle the circular railway track of radius 200 m must be banked for speed 72 km/hr?

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