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Laws Of Motion

Question
CBSEENPH11017017

The strength of a string is twice the weight of a body attached to one end of string. From what angle the mass must be released so that string just breaks when at the lowest point?

Solution
When string subtends an angle θ with vertical, the mass will be at height h = r(l – cosθ) from the lowest point.
                    
Therefore velocity of mass m at the lowest point when released is,
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Tension in the string at the lowest point is,
      T equals m g plus fraction numerator m v squared over denominator r end fraction equals m g plus 2 m g left parenthesis 1 minus cos theta right parenthesis
String will just break when tension at the lowest point is equal to 2mg,
m g plus 2 m g left parenthesis 1 minus cos theta right parenthesis equals 2 m g
rightwards double arrow              1 minus cosθ equals 1 half
rightwards double arrow                   cosθ equals 1 half
rightwards double arrow                   space space space straight theta equals 60 degree