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Motion In Straight Line

Question
CBSEENPH11017005

A car is moving with a constant speed of 30km/hr along a straight line towards a vertical wall. A fly flying at a constant speed of 60km/hr starts from a wall towards the car when it is 90km away from the wall. The fly flies till it reaches the glass pane of car and then returns to wall at the same speed. After touching the wall again it flies towards car. Fly continues its motion till car just touches the wall. Find the total distance travelled by fly. How many trips the fly will make?

Solution

Speed of car, v = 30 km/hr
Distance of wall, d= 90 km 
Time taken by car to reach the wall is,
straight t space equals space straight d over straight v equals 90 over 30 equals 3 hr
Fly moves back and forth between car and the wall with constant speed 60km/hr.
Therefore, distance travelled by fly is,

S = ut
   = 60 x 3
   = 180 km
To find: The distance travelled by the fly in it's one complete trip. 

Consider, initially when the fly is flying from the wall towards the car, it is at a distance D from the wall. 
Speed at which the car is approaching the fly = 30 km/hr
Speed at which the fly is flying towards the car = 60 km/hr
Let both car and fly meet after time t1.

Thus distance travelled by car and fly respectively is,

 straight d subscript 1 straight c end subscript space equals space vt subscript 1 space equals space 30 space straight t subscript 1 space space space space space space space space space space space space space space space space space... space left parenthesis 1 right parenthesis space

straight d subscript 1 straight f end subscript space equals space vt subscript 1 space equals space 60 space straight t subscript 1 space space space space space space space space space space space space space space space space space... space left parenthesis 2 right parenthesis

Therefore comma space

straight d subscript 1 straight c end subscript space plus straight d subscript 1 straight f end subscript space equals space straight D

Now comma space solving space equations space left parenthesis 1 right parenthesis comma space left parenthesis 2 right parenthesis space and space left parenthesis 3 right parenthesis comma space
we space have

straight d subscript 1 straight c end subscript space equals space straight D over 3 space space space space space space space space and space straight d subscript 1 straight f end subscript space equals space fraction numerator 2 straight D over denominator 3 end fraction
The fly will return to the wall. 
Let t2 be the time taken by fly to come back to the wall. 
straight t subscript 2 space equals space space straight d subscript 1 straight F end subscript over straight v space equals space fraction numerator 2 straight D over denominator 3 cross times 60 end fraction space equals space straight D over 90 space
In time t2, the distance moved by the car towards the fly is
straight d subscript 2 straight c end subscript space equals space Vt subscript 2 space equals space 30 straight D over 90 space equals space straight D over 3
Distance travelled by the car after completing 1 trip is, 
d = straight d subscript 1 straight c end subscript space plus space straight d subscript 2 straight c end subscript space equals space fraction numerator 2 straight D over denominator 3 end fraction
When fly completes one trip, distance of car from the wall is, 
straight D subscript 1 space equals space straight D space minus space fraction numerator 2 straight D over denominator 3 end fraction
Thus, if at the beginning of motion, the car is at a distance D from the wall, then after completion of one trip of fly, it will be at a distance one-third of initial distance i.e. 1/3 D from the wall. 
Thus, the distance of car from wall after n trips will be 
 space space space space 1 over 3 to the power of straight n space straight D space equals space 0

rightwards double arrow space straight n space equals space infinity
Therefore, the fly will make infinitely many trips.