-->

Motion In Straight Line

Question
CBSEENPH11017092

A ball is thrown vertically upwards from the top of a tower 80m high and reach the ground in 6 seconds. Find the velocity with which the ball is thrown?

Solution
Consider, ground as reference point and vertically upward direction as positive. 
Height of the tower, h = 80 m 
Acceleration due to gravity, a = -10 m/s2 
Time taken for the ball to reach the ground = 6 seconds
Here, 
straight x subscript 0 space equals space straight h space equals space 80 space straight m space space space space space space space straight a space equals space straight g space equals space minus 10 space straight m divided by straight s squared
straight t space equals space 6 space sec space space space space space space space space space space space space space space space space space space straight x space equals space 0 space
Let  be the initial velocity of the ball. 
So, usign equation of motion, we have
space space space space space space space space straight x space equals space straight x subscript 0 space plus space ut space plus space 1 half at squared space
therefore space space space space space 0 space equals space 80 space plus space straight u cross times 6 space minus 1 half cross times 9.8 cross times left parenthesis 6 right parenthesis squared space
space space space space space space space space space 0 space equals space 80 space plus space 6 straight u space minus 1 half cross times 9.8 space cross times 36 space
space space space space space space space space space 0 space equals space 80 space plus space 6 straight u space minus 176.4 space space

space space space space space space space space space straight u space equals space 16.07 space straight m divided by straight s

So, u = 16.07 m/s is the velocity with which the ball is thrown.