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Motion In Straight Line

Question
CBSEENPH11017063

A stone falls from a cliff and travels 45m in last second before it reaches the ground. What is the height of cliff? (Given g = 10 m/s2)

Solution

Let, height of the cliff be 'h'. 

Time taken by the stone to reach the ground = n 

The distance travelled by particle in nth second is given by, 
                   Snth=u+a2(2n-1)

Here we have, 

Snth=45m,   u = 0,   a = 10 m/s2

   45=0+102(2n-1) 

     n = 5 s 

i.e. Stone takes 5 s to reach the ground from top of cliff. 

Now the height of cliff is,

h =ut+12gt2   =0×5+12×10×(5)2   =125m