-->

Laws Of Motion

Question
CBSEENPH11017061

A car travels on a flat, circular track of radius 200 m at 30 m/s and has a centripetal acceleration = 4.5 m/s2. a) If the mass of the car is 1000 kg, what frictional force is required to provide the acceleration? b) If the coefficient of static friction is 0.8, what is the maximum speed at which the car can circle the track?

Solution
Here given,
Radius, r = 200 m
Velocity, v = 30 m/s
Centripetal acceleration, a  = 4.5 m/s2 
Mass, m = 1000 kg 
Frictional force required, F = ? 
Frictional force is the same as accelerating force. 
Therefore, 
a) ma = 1000 cross times space 4.5 =4500 N 
b) Coefficient of static friction, straight mu space equals space 0.8 space space
Maximum speed, v = ?

straight v space equals space square root of μrg space equals space square root of 0.8 cross times 200 cross times 9.8 end root space equals space 39.6 space straight m divided by straight s