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Laws Of Motion

Question

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A hunter has a machine gun that can fire 50 gram bullets with a velocity of 150 m/s. A 60 kg tiger springs at him with a velocity of 10 m/s. How many bullets must the hunter fire per second into the tiger in order to stop him in his track?

Solution

Let, n bullets be fired in one second.
To stop the tiger, momentum of bullets = momentum of tiger.
n x ( 50 x 10^-3) x 150 = 60 x 10
n = $fraction numerator 60 space cross times space 10 over denominator 50 space cross times space 10 to the power of negative 3 end exponent space cross times space 150 end fraction space equals space 80$

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