A curved road of diameter 1.8 km is banked so that no friction is required at a speed of 30 m/s. What is the banking angle?

Solution

Diameter, 2 r = 1.8 km = 1800 m
r = 1800/2 = 900 m
Speed, v = 30 m/s
Banking angle, $straight theta$ = ?
We know that,
$tan space straight theta space equals space fraction numerator straight v squared over denominator straight r space straight g end fraction space equals space fraction numerator 300 space straight x space 30 over denominator 900 space straight x space 9.8 end fraction space equals space 0.102 That space is comma space straight theta space equals space 6 to the power of straight o$

Some More Questions From Laws of Motion Chapter

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Laws Of Motion

A curved road of diameter 1.8 km is banked so that no friction is required at a speed of 30 m/s. What is the banking angle?

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