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Laws Of Motion

Question
CBSEENPH11017045
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In an X-ray machine, an electron is subjected to a force of 10-23 N. In how much time will the electron cover a distance of 0.1 m. Take mass of electron as 10-30 kg. 

Solution

Given, 
Force, F = 10-23 N, t = ?
s = 0.1 m, m = 10-30 kg 
Acceleration, a = straight F over straight m space equals space 10 to the power of negative 23 end exponent over 10 to the power of negative 30 end exponent space equals space 10 to the power of 7 space m divided by s squared
Using the equation of motion, 
straight s space equals space ut space plus space 1 half at squared space 0.1 space equals space 0 space plus space 1 half space cross times space 10 to the power of 7 space straight t squared space straight t squared space equals space 2 space cross times space 10 to the power of negative 8 end exponent space rightwards double arrow space straight t space equals space 1.414 space cross times space 10 to the power of negative 4 end exponent space straight s

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