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Measures Of Dispersion

Question
CBSEENST11024409

With an example, prove that the sum of the square of the deviations from arithmetic mean is least i.e. less than the sum of the squares of the deviations of observations taken from any other value.

Solution

a) Calculation of sum of the squares of the deviation from A.M. from an imaginary data:

X

 

(n)

(n)2

1

–2

4

2

–1

1

3

0

0

4

+ 1

1

5

+ 2

4

 

Σn2 = 10

Here, sum of the square of the deviations from A.M. is 3

... (i)

(b) Calculation of sum of the square of the deviation taken from any other value i.e. 2 (except A.M.)

X

 

(n)

(n)2

1

–1

1

2

0

0

3

+ 1

1

4

+ 2

4

5

+ 3

9

Σ

 

Σn2 = 15

Here, sum of the square of the deviation taken from any other value except A. M. is 15 ... (ii)

From (i) and (ii) we come to know that the sum of the square of the deviations from arithmetic mean is less.