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Correlation

Question

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Calculate Karl Pearson’s correlation co-efficient bv the assumed mean method.

X

14

15

18

20

25

30

Y

40

45

65

28

30

40

Solution

Calculate of Karl Pearson’s correlation co-efficient.

X	Y	dX	dY	dXdY	dX²	dY²
14	40	–6	–5	30	36	25
15	45	–5	0	0	25	0
18	65	–2	20	–40	4	400
20	28	0	–17	0	0	289
25	30	5	–15	–75	25	225
30	40	10	–5	–50	100	25
N= 6		IΣdX = 2	Σ dY = 22	ΣdXdY = –13.5	Σ dX² = 190	Σ dY² = 964

A.M. of X series =20 A.M. of Y series = 45

Some More Questions From Correlation Chapter

The range of simple correlation coefficient is:

If r_xy is positive the relation between X an Y is of the type:

If r_xy = 0 the variable X and Y are:

Of the following three measures which can measure any type of relationship:

If precisely measured data are available the simple correlation coefficient is:

Why is r preferrred to co-variance as a measure of association?

Can r lie outside -1 and 1 range depending on the type of data?

Does correlation imply causation?

When is rank correlation more precise than simple correlation coefficient?

Does zero correlation mean independenc?

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