Question
In a certain examination there were 100 candidates of whom 21 failed, 6 secured distinction, 43 were placed in the third division and 18 in second division. It is know that atleast 75% marks are required for distinction, at least 40% for passing, at least 50% for second division and at least 60% for first division. Calculate the median of the distribution of marks.
Solution
No. of candidate = 100
Failed = 21
Passed =100-21 = 79
Secured distinction = 6
3rd divisioner = 43
2nd divisioner = 18
1st divisioner = 18 (79 - 43 - 18)
(including distinction holders)
|
Class Interval |
f |
cf |
|
0-40 40-50 50-60 60-70 75 and above |
21 43 18 12 6 |
21 64 82 94 100 |
|
Σ f = 100 |
The value of 50th item lies in 40 - 50 class interval.
