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Measures Of Dispersion

Question
CBSEENST11024276

To check the quality of two brands of lightbulbs, their life in burning hours was estimated as under for 100 bulbs of each brand.

Life (in hrs)

No. of bulbs

Brand A

Brand B

0–50

15

2

50–100

20

8

100–150

18

60

150–200

25

25

200–250

22

5

 

100

100

(i) Which brand gives higher life?

(ii) Which brand is more dependable?

Solution

Brand A of light bulbs

Life

No. of

Mid-points

d

d1

fd'

fd2

(in hrs)

Bulbs (f)

(m)

(m – 125)

   

0–50

15

25

–100

–2

–30

60

50–100

20

75

–50

–1

–20

20

100–150

18

125

0

0

0

0

150–200

25

175

50

+1

25

25

200–250

22

250

100

2

44

88

 

N = 100

     

Σfd' = 19

Σfd2 =193

Brand B

Life

No. of

M.V.

d

fd'

fd'2

(in hrs)

Bulbs

(m)

 

d1

   

0–50

2

25

–100

–2

–4

8

50–100

8

75

–50

–1

–8

8

100–150

60

125

0

0

0

0

150–200

25

175

+50

+1

+25

25

200–250

5

225

+100

+2

+10

20

 

N= 100

     

Σfd' =23

Σfd'2 = 61

(i) Since the average life of bulbs of Brand B (136.5) is greater than that of Brand A (134.5 hrs), therefore the bulbs of Brand B givens a higher life.

(ii) Since CV of bulbs of Brand B (27.34%) is less than that of Brand A (51.15%), therefore, the bulbs of Brand B are more dependable.