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Measures Of Central Tendency

Question
CBSEENST11024256

With example that if there are unequal class intervals in a series, then the median will be same without matching the equal class intervals.

Solution

We can prove it by taking the following table:

Marks

No. of Students

0-10

10-30

30-60

60-80

80-90

5

12

28

10

5

Calculation of median without adjusting the class-intervals.

X

f

cf

0-10

10-30

30-60

60-80

80-90

5

12

28

10

5

5

17

45

55

60

Total

Σ P = 60

 

The value of 30th item lies in 30-60 class interval.

Now we convert the unequal class intervals into equal intervals and calculate the median

Marks

Quantity
(f)

Cumulative Frequency (cf)

0-30

30-60

69-90

5+12 = 17

28

10+5 =15

17

45

60

 

60

 

The value of 30th item lies in 30-60 class interval

Then we see that the median is same by the both method.