Sponsor Area

Acids, Bases And Salts

Question
CBSEENSC10014841

a) What is meant by the 'power of a lens'?
b) State and define the S.I. unit of power of a lens.
c) A convex lens of focal length 25 cm and a concave lens of focal length 10 cm are placed in close contact with each other.
Calculate the lens power of this combination.

Solution

a) The ability of a lens to converge or diverge a beam of the light ray is known as the Power (P) of the lens.
Power is equal to the reciprocal of the focal length.
That is, P = 1 over straight f
b) SI unit of the power of a lens is Dioptre.
1 diopter = fraction numerator 1 over denominator left parenthesis 1 straight m right parenthesis end fraction = 1 m-1
1 m is the focal length of the lens.
c) Given,
Focal length, f = +25 cm
                   = plus open parentheses 25 over 100 close parentheses straight m
 straight P subscript 1 space equals space 1 over straight f subscript 1
space space space space space equals space 100 over 25
rightwards double arrow space straight P subscript 1 space equals space plus 4 space straight D
Focal length, f2 = -10 cm = negative open parentheses 10 over 100 close parentheses m
Power, P21 over straight f subscript 2 space equals space minus open parentheses 100 over 10 close parentheses m space equals space minus space 10 space D
Power of the combination of lens, P = P1 + P2
P = 4 D - 10 D = - 6 D