Sponsor Area

Acids, Bases And Salts

Question
CBSEENSC10014743

One-half of a convex lens of focal length 10 cm is covered with a black paper. Can such a lens produce an image of a complete object placed at a distance of 30 cm from the lens? Draw a ray diagram to justify your answer.

A 4 cm tall object is placed perpendicular to its principal axis of a convex lens of focal length 20 cm. The distance of the object from the lens is 15 cm. Find the nature, position and the size of the image.

Solution

The convex lens will produce the complete image of the object even though half of the lens is covered. This is because the other half of the lens can refract the light coming from the object. However, the intensity of the image will be reduced.

Numerical:
Given,
Height of the object, h = 4 cm
Focal length of the convex lens, f = 20 cm
Object distance, u = -15 cm
Using the lens formula,
1 over straight f equals 1 over v minus 1 over u
Therefore,
1 over straight v equals 1 over f plus 1 over u
space space space space equals space 1 over 20 minus 1 over 15
space space space space equals space fraction numerator 3 minus 4 over denominator 60 end fraction
space space space space space equals space fraction numerator negative 1 over denominator 60 end fraction
v space equals space minus 60 space c m
Thus, the image is formed 60 cm in front of the lens on the same side as that of the object.
Since v is negative, the image formed is virtual.
Using the formula for magnification of a lens,
straight m space equals space fraction numerator straight h apostrophe over denominator straight h end fraction equals straight v over straight u
That is,
h' = vh over straight u equals fraction numerator negative 60 x 4 over denominator negative 15 end fraction equals 16 space c m
Since the height of the image is positive and greater than the height of the object, the image formed is erect and magnified.
Therefore, the image is virtual, erect and magnified.