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Acids, Bases And Salts

Question
CBSEENSC10014631

List the sign conventions for reflection of light by spherical mirrors. Draw a diagram and apply these conventions in the determination of focal length of a spherical mirror which forms a three times magnified real image of an object placed 16 cm in front of it.

Solution

: Sign conventions for spherical mirrors

I. Objects are always placed to the left of the mirror i.e. light must fall on the mirror from left to right.

II. All distances are measured from the pole of the mirror.

III. Distances along the direction of the incident ray (along positive X - axis) are taken as positive, while distances along the direction of the reflected ray (along negative X-axis) are taken as negative.

IV. Heights measured perpendicular to and above the principal axis (along positive Y-axis) are taken as positive.

V. Heights measured perpendicular to and below the principal axis (along negative Y-axis) are taken as negative.

 

 

 

Given,

Magnification, m = −3 (real image is inverted always)

Object distance, u = −16 cm

Now,

 straight m equals space minus straight v over straight u space equals negative fraction numerator straight v over denominator left parenthesis negative 16 right parenthesis end fraction space equals straight v over 16

minus 3 space equals straight v over 16
straight v equals negative 48 space cm
where space straight v space is space the space image space distance

Using space mirror space formula comma

1 over straight f equals 1 over straight v plus 1 over straight u
1 over straight f equals fraction numerator 1 over denominator left parenthesis negative 48 right parenthesis end fraction plus fraction numerator 1 over denominator left parenthesis negative 16 right parenthesis end fraction equals negative 1 over 12

straight f minus 12 space cm space

straight f space is space the space required space focal space length