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Life Processes

Question
CBSEENSC10014628

While performing the experiment with raisins to determine the percentage of water absorbed by them, a student made following measurements:

Mass of water in the beaker = 40 g

Mass of raisins before soaking = 5 g

Mass of raisins after soaking for 2 hours = 8 g

Mass of water left in the beaker after the experiment = 35 g

The percentage of water absorbed by raisins is:
  • begin inline style fraction numerator 40 straight g space minus space 35 straight g over denominator 35 straight g end fraction end style space cross times space 100
  • fraction numerator 40 straight g space minus space 35 straight g over denominator 40 straight g end fraction space cross times space 100
  • fraction numerator 8 straight g space minus space 5 straight g over denominator 8 straight g end fraction space cross times space 100
  • fraction numerator 8 straight g space minus space 5 straight g over denominator 5 straight g end fraction space cross times space 100

Solution

D.

fraction numerator 8 straight g space minus space 5 straight g over denominator 5 straight g end fraction space cross times space 100

The percentage of water absorbed by raisins is calculated by using the formula
fraction numerator straight W subscript 2 space minus straight W subscript 1 over denominator straight W subscript 1 end fraction space cross times space 100

where, W2 is the weight of wet resin and W1 is the weight of dry resin.