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Acids, Bases And Salts

Question
CBSEENSC10014485
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A spherical mirror produces an image of magnification −1 on a screen placed at a distance of 50 cm from the mirror.

(a) Write the type of mirror.

(b) Find the distance of the image from the object.

(c) What is the focal length of the mirror?

(d) Draw the ray diagram to show the image formation in this case.

Solution

 a) The image formed is real because magnification is negative. Therefore, the type of mirror used is a concave mirror.

b)  Magnification comma space straight m equals space minus straight v over straight u space equals negative 1 therefore comma space straight u equals straight v equals negative 50 space cm

 

So, distance of the image from the object = |u| +|v| =100 cm

c) Using the mirror formula, we have
1 over straight f space equals 1 over v plus 1 over u equals fraction numerator 1 over denominator negative 50 end fraction plus fraction numerator 1 over denominator negative 50 end fraction equals negative 1 over 25 

 

 

d) The given diagram shows the image formation.

Some More Questions From Acids, Bases and Salts Chapter

What do you mean by reflection, refraction and absorption of light?

Which type of phenomenon (reflection or refraction) occurs when light falls on (i) a highly polished surface like a mirror and (ii) a transparent medium like glass or water?

What is meant by the optical image of an object?

What are real and virtual images? Can these images be obtained on a screen? Give reasons in support of your answer.

Give three points of differences between real and virtual images.

What is a mirror? Mention the different types of mirrors commonly used.

Define the following terms in connection with reflection of light:
Incident ray, reflected ray, point of incidence, normal, angle of incidence and angle of reflection.

State the laws of reflection of light.

Are the laws of reflection applicable to plane surfaces also valid for curved surfaces?

State the important properties of images formed by plane mirrors.

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