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Acids, Bases And Salts

Question
CBSEENSC10012984

Draw a ray diagram to show the formation of the image of an object placed between f and 2f of a thin concave lens. Deduce the relation between the object distance, the image distance and the focal length of the lens under this condition.

Solution
Derivation of lens formula for a concave lens:

The ray diagram for the formation of image of an object which is placed between F
1 and 2F1 of a thin concave lens is shown in Fig.

The image A'B' formed is virtual and erect.



A'B'O and ABO are similar,

    A'B'AB= OB'OB                             ...(1)

 A'B'F  and  OMF  are similar,

   A'B'MO = B'FOF

But MO = AB,

   A'B'AB = B'FOF                                  ...(2)

From (1) and (2), we get

         OB'OB =B'FOF =OF-OB'OF

According to new cartesian sign convention,
Object distance,  OB = -u
Image distance,  OB' = -v
Focal length, OF = -f

Relation between u,v anf f can be established as follows:

          -v-u = -f+v-f 

             vf = uf - uv 

            uv = uf - vf 

Dividing both sides by uvf, we get 

               1f = 1v-1u 

which is the required relation between u, v and f for a concave lens.