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Question
CBSEENSC10012793

Discuss the refraction through a rectangular glass slab and show that the emergent ray is parallel to the incident ray but laterally displaced. How does lateral displacement depend on the thickness of the glass slab?
Or
With the help of a ray diagram, show that when light falls obliquely on a side of rectangular slab, the emergent ray is parallel to the incident ray.
Show the lateral displacement of the ray on the diagram.

Solution

Refraction through a rectangular glass slab:

Consider a rectangular glass slab PQRS, as shown in figure below. On the face PQ, a ray AB is incident at an angle of incidence i1. It bends towards the normal, on entering the glass slab, and travels along BC inclined at an angle of refraction r1. The refracted ray BC is incident on the face SR at an angle of incidence i2. The emergent ray CD bends away from the normal at an angle of refraction r2

Now, using Snell’s law, we have
Refraction from air to glass at face PQ, 

                      sin i1sin r1 = ngna                  ...(1) 

where, 
na is the refractive index of sir and
ng is the refractive index of glass. 


 
Fig. Refraction through a glass slab

Using Snell’s law for refraction from glass to air at face SR, we have 

                 sin i2sin r2 = nang 

But                   i2 = r1,

Therefore,
                     sin r1sin r2 = nang                    ...(2) 

Multiplying equations (1) and (2), we get 

                     sin  i1sin r1× sin r1sin r2 = 1 

                 sin i1 = sin r2 

i.e.,                     i1 = r2 

Thus, the emergent ray CD is parallel to the incident ray AB, but it has been laterally displaced by a perpendicular distance CN with respect to the incident ray. This lateral shift in the path of light on emerging from a medium with parallel faces is called lateral displacement.

It is found that the lateral displacement is directly proportional to the thickness of the glass slab.