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Acids, Bases And Salts

Question
CBSEENSC10012765

Establish the relationship between object distance u, image distance v and radius of curvature f for a convex mirror.

Solution
Mirror formula for a convex mirror:

Consider a convex mirror of small aperture where we assume, P be the pole, F the principal focus and C the centre of curvature.

Let PF = f be the focal length and PC = R be the radius of curvature of the mirror.
Here,  AB is an object placed in front of the mirror perpendicular to its principal axis.
A' B' is the virtual, erect image of the object AB formed (behind the mirror) after reflection at the convex mirror. 

 

Fig. Image formed by a convex mirror

Using the new cartesian sign convention, we have

Object distance, BP = - u 
Image distance, PB' = + v
Focal length, FP = +f
Radius of curvature,  PC = + R = +2f 

Now, 
 A' B' C  ~  ABC                      
                                              A'B'AB = B'CBC = PC-PB'BP+PC = 2f-v-u+2f         ...(1)


As A' B'P = BPQ = APB

Therefore,  A' B' P ~  ABP. 

Consequently, 

                   A'B'AB =PB'BP = ν-u                ...(2) 

From equations (1) and (2), we get 

                  2f-ν-u+2f = ν-u 

            -2uf+uv = -uv + 2νf 

                       = νf + uf 

Dividing both sides by uvf, we get 

                        1f = 1u+1v   

                     2R = 1u + 1v 

which is the required mirror formula for a convex mirror.