Question
A person clapped his hands near a cliff and heard the echo after 5 s. What is the distance of the cliff from the person if the speed of the sound, v is taken as 342 ms–1?
Solution
Speed of sound in air, v = 342 ms-1
Time taken for hearing the echo, t = 3 s
Distance travelled by the sound = vt
= 342 x 3
= 1026 m
In 3 s, sound has to travel twice the distance between the the cliff and the person.
Hence the distance between the cliff and the person is given by, d= 1730 m/2 = 865 m
Time taken for hearing the echo, t = 3 s
Distance travelled by the sound = vt
= 342 x 3
= 1026 m
In 3 s, sound has to travel twice the distance between the the cliff and the person.
Hence the distance between the cliff and the person is given by, d= 1730 m/2 = 865 m
