Certain force acting on a 20 kg mass changes its velocity from 5 ms-1 to 2 ms-1. Calculate the work done by the force.
Given,
Mass, m = 20 kg
Initial velocity, u= 5 ms-1
Final velocity, v= 2 ms-1
Work done = change in K. E.
W = mv2 - mu2
= m ( v2 - u2)
= x 20 x (22 - 52)
= 10 (4-25)
= -10 x 21
= -210 J
Here, the negative sign implies the retarding nature of the applied force.