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Matter In Our Surroundings

Question
CBSEENSC9006285

Certain force acting on a 20 kg mass changes its velocity from 5 ms-1 to 2 ms-1. Calculate the work done by the force.

Solution

Given,

Mass, m = 20 kg
Initial velocity, u= 5 ms-1 
Final velocity, v= 2 ms-1

Work done = change in K. E.

             W = 12 mv2 - 12 mu2

                 = 12 m ( v- u2)

                 = 12 x 20 x (22 - 52)

                 = 10 (4-25)

                 = -10 x 21

                 = -210 J

Here, the negative sign implies the retarding nature of the applied force.