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Atoms And Molecules

Question
CBSEENSC9006170
Wired Faculty App

Density of gold is 19300 kg/m3. What will be the mass of a gold brick with dimensions of 5 cm x 10 cm x 20 cm?

Solution
Density of gold = 19300 kg/m3

Dimension of the brick = 5 cm x 10 cm x 20 cm

Therefore, 

Volume = l×b×h

            = 5 x 10 x 20 cm3

            = 5 x 10 x 10-6 m3

            = 10-3 m3

So, Mass = Volume x Density

              = 10-3 x 19300

              = 19.3 kg

Some More Questions From Atoms And Molecules Chapter

When 3.0 g of carbon is burnt in 8.00 g oxygen, 11.00 g of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00 g of carbon is burnt in 50.00 g of oxygen ? Which law of chemical combination will govern your answer?

What are polyatomic ions? Give examples.

Write the chemical formulae of the following:

(a) Magnesium chloride
(b) Calcium oxide
(c) Copper nitrate 
(d) Aluminium chloride
(e) Calcium carbonate

Give the names of the elements in the following compounds.

(a) Quick lime
(b) Hydrogen bromide
(c) Baking powder 
(d) Potassium sulphate.

Calculate the molar mass of the following substances:

(a) Ethylene
(b) Sulphur molecule, S8
(c) Phosphorus molecule, P4
(d) Hydrochloric acid, HCl
(e) Nitric acid, HNO3.

What is the mass of:

(a) 1 mole of nitrogen atoms

(b) 4 moles of aluminium atoms

(c) 10 moles of sodium sulphite.

Convert into mole

(a) 12 gm of oxygen gas

(b) 20 gm of water

(c) 22 gm of carbon dioxide.

What is the mass of?

(a) 0.2 mole oxygen atoms.

(b) 0.5 mole of water molecules.

Calculate the number of molecules of sulphur (S8) present in 16 gm of solid sulphur.

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