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Matter In Our Surroundings

Question
CBSEENSC9006364

A body of mass 25 kg is raised to the top of a building 10 m high and then dropped freely under gravity (g = 10 m/s2):

(a) Calculate the work done in raising the body to the top of the building.

(b) What is the value of the gravitational potential energy at the top of the building?

(c) By what factor will the gravitational potential energy of the same body increase if it is raised to the top of a multistorey building 30 m high?

(d) When will the kinetic energy of the body be maximum?

Solution

Given that,
Mass of the body, m = 25 kg
Height to which the object is rasied up, h = 10 m
Acceleration due to gravity, g = 10 m/s2

(a) Work done  = mgh
                       = 25 x 10 x 10 J
                       = 2500 J. 
(b) Gravitational P.E. = work done = 2500 J 
(c) Gravitational P.E. at a height of 30 m is,
     P.E= 25 x 30 x 10 J = 7500 J
therefore space space space space fraction numerator straight P. straight E. space at space 30 space straight m space height over denominator straight P. straight E. space at space 10 space straight m space height end fraction space equals space fraction numerator 7500 space straight J over denominator 2500 space straight J end fraction space equals space 3

space Thus comma space space straight P. straight E. space increases space by space 3 space times. space
(d) K.E. of the body will be maximum just before the body strikes the ground.