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Matter In Our Surroundings

Question
CBSEENSC9006323

The work done on a body of mass 10 kg to lift it through a certain height is 490 J. Calculate the height through which the body is lifted. Take g = 9.8 m/s2.

Solution

Given comma space

Mass space of space the space body comma space space straight m space equals space 10 space kg

Work space done comma space straight W space equals space 490 space straight J

Distance space travelled comma space straight s space equals space ?

Using space the space formula comma space

space space space space space space space space space space space space space space space straight W space equals space Fs

space space space space space space space space space space space space space space space space space space space space equals space mg space cross times space straight s

therefore space height space through space which space the space body space is space lifted comma space straight s space equals space straight W over mg
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 490 over denominator 10 space cross times space 9.8 end fraction space equals space 5 space straight m.