A force of 5 N is acting on an object. The object is displaced through 2 m in the direction of the force, as shown in Fig. 11.5. If the force acts on the object all through the displacement, then what is the work done?
(Textbook Example 11.1)
Consider the object on which the force is acting upon as shown in the fig. below.
We have,
Force, F = 5 N
Displacement, s = 2 m
Therefore,
Work done, W = Fs = 5N = 10 Nm = 10 J