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Is Matter Around Us Pure

Question
CBSEENSC9005952

A driver accelerates his car first at the rate of 1.8 m/s2 and then at the rate of 1.2 m/s2. Calculate the ratio of the force exerted by the engine in the two cases.

Solution

Initial rate of acceleration = 1.2 m/s2
Rate of acceleration = 1.2 m/s2
Let m be the mass of the car. 
Then,
Ratio of the force exerted by the engine is, 
 space space straight F subscript 1 over straight F subscript 2 space equals space ma subscript 1 over ma subscript 2 space equals space fraction numerator 1.8 over denominator 1.2 end fraction space equals space 18 over 12 space equals 3 over 2.


Therefore, the ratio is 3:2. 

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Pragya tested the solubility of three different substances at different temperatures and collected the data as given below (results are given in the following table, as grams of substance dissolved in 100 grams of water to form a saturated solution).

Substance Dissolved

Temperature in K

283

293

313

333

353

Potassium nitrate

21

32

62

106

107

Sodium chloride

36

36

36

37

37

Potassium chloride

35

35

40

46

54

Ammonium chloride

24

37

41

55

66



What mass of potassium nitrate would be needed to produce a saturated solution of potassium nitrate in 50 grams of water at 313 K?