+91-8076753736[email protected]
logo
logo
-->

Is Matter Around Us Pure

Question
CBSEENSC9005950
Wired Faculty App

A constant force acts on an object of mass 5 kg for a duration of 2 s. It increases the object’s velocity from 3 ms–1 to 7 ms–1. Find the magnitude of the applied force. Now if the force were applied for a duration of 5 s, what would be the final velocity of the object.

Solution
In space the space first space case colon space Initial space velocity comma space straight u space equals space 3 space ms to the power of negative 1 end exponent Final space velocity comma space straight v space equals space 7 space ms to the power of negative 1 end exponent Time space taken comma space straight t space equals space 2 space straight s Mass space of space the space body comma space straight m space equals space 5 space kg Therefore comma space Acceleration comma space space straight a space equals space fraction numerator straight v minus straight u over denominator straight t end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 7 minus 3 over denominator 2 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 4 over 2 space equals space 2 space m s to the power of negative 2 end exponent Now comma space using space Newton apostrophe straight s space forst space law space of space moton comma space F o r c e comma space straight F space equals space m a space equals space 5 cross times 2 space equals space 10 space straight N. space
The same force is applied for a duration of 5 s, therefore the acceleration a will remain same.
I n space s e c o n d space c a s e colon I n i t i a l space v e l o c i t y comma space straight u space equals space 3 space m s to the power of negative 1 end exponent T i m e space t a k e n comma space straight t space equals space 5 straight s A c c e l e r a t i o n comma space straight a space equals space 2 space m s to the power of negative 2 end exponent S o space u s i n g space f i r s t space e q u a t i o n space o f space m o t i o n comma space space space space space space space space space straight v space equals space straight u plus a t space space space space space space space space space space space space space equals space 3 plus 2 cross times 5 space space space space space space space space space space space space space equals space 13 space m s to the power of negative 1 end exponent. space

Some More Questions From Is Matter Around Us Pure Chapter

Which separation techniques will you apply for the separation of the following?

Sodium chloride from its solution in water.

Which separation techniques will you apply for the separation of the following?

Ammonium chloride from a mixture containing sodium chloride and ammonium chloride.

Which separation techniques will you apply for the separation of the following?

Small pieces of metal in the engine oil of a car.

Which separation techniques will you apply for the separation of the following?

Different pigments from an extract of flower petals.

Which separation techniques will you apply for the separation of the following?

Butter from curd.

Which separation techniques will you apply for the separation of the following?

Oil from water.

Which separation techniques will you apply for the separation of the following?

Tea leaves from tea

Which separation techniques will you apply for the separation of the following?

Iron pins from sand.

Which separation techniques will you apply for the separation of the following?

Wheat grains from husk

Which separation techniques will you apply for the separation of the following?


Fine mud particles suspended in water.

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation