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Is Matter Around Us Pure

Question
CBSEENSC9005943

A motorcar is moving with a velocity of 108 km/h and it takes 4 s to stop after the brakes are applied. Calculate the force exerted by the brakes on the motorcar if its mass along with the passengers in the motorcar is 1000 kg.

Solution

Here,
Initial velocity of motorcar, u = 108 km h-1 
                                            equals space 108 space cross times space 5 over 18 space
equals space 30 space ms to the power of negative 1 end exponent
The brakes are aplied and motorcar comes to rest.
So,
Final velocity= 0
Time taken for the motorcar to stop, t = 4s
MAss of the motorcar, m = 1000 kg
therefore  Force, 
straight F equals space straight m open parentheses fraction numerator straight v minus straight u over denominator straight t end fraction close parentheses space equals space 1000 space open parentheses fraction numerator 0 minus 30 over denominator 4 end fraction close parentheses space equals space minus 750 space straight N.

The negative sign shows that the force exerted by the brakes is opposite to the direction of motion of motorcar. 

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Substance Dissolved

Temperature in K

283

293

313

333

353

Potassium nitrate

21

32

62

106

107

Sodium chloride

36

36

36

37

37

Potassium chloride

35

35

40

46

54

Ammonium chloride

24

37

41

55

66



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Substance Dissolved

Temperature in K

283

293

313

333

353

Potassium nitrate

21

32

62

106

107

Sodium chloride

36

36

36

37

37

Potassium chloride

35

35

40

46

54

Ammonium chloride

24

37

41

55

66