Question
A bullet of mass 10 g travelling horizontally with a velocity of 150 ms–1 strikes a stationary wooden block and comes to at rest in 0.03 s. Calculate the distance of penetration of the bullet into the block. Also calculate the magnitude of the force exerted by the wooden block on the bullet.
Solution
Here,
Mass of the bullet, m = 10 g = 0.01kg
Velocity with which the bullet is fired, u = 150 ms-1,
Final velocity, v = 0 m/s
Time taken for the bullet to strike the object, t = 0.03 s
Now, using the formula,
Acceleration is negative.
The distance of penetration of the bullet into the block is given by the second equation of motion,
