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Matter In Our Surroundings

Question
CBSEENSC9005774

Fgure 8.26 shows the distance-time graphs of two trains, which start moving simultaneously in the same direction. From the graphs, find:

(i) How much ahead of A is B when the motion starts?

(ii) What is the speed of B?

(iii) When and where will A catch B?

(iv) What is the difference between the speeds of A and B?



Solution

(i) When the motion started, B is ahead of A by distance OP = 100 km
left parenthesis ii right parenthesis space Speed space of space straight B space equals space QR over PR space equals space fraction numerator 150 minus 100 over denominator 2 minus 0 end fraction space equals space 25 space km divided by straight h. space

(iii) As it is clear from graphs, A will catch B at point Q, i.e., after 2 hours and at a distance of 150 km.
left parenthesis iv right parenthesis space space space space Speed space of space straight A space equals space QS over OS space equals space fraction numerator 150 minus 0 over denominator 2 minus 0 end fraction space equals space 75 space km divided by straight h
therefore space space space Difference space in space speeds space equals space 75 minus 25 space equals space 50 space km divided by straight h.