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Matter In Our Surroundings

Question
CBSEENSC9005730

Establish the relation v 2 – u2 = 2as, where ‘u’ is the initial velocity, ‘v’ the final velocity, ‘a’ the uniform acceleration and ‘s’ is the distance covered by the body.

Solution

Third equation of motion:
Let a body start with initial velocity u. After covering distance 's' under uniform acceleration 'a', its velocity becomes 'v' in 't'  seconds.
Then, 
Average space velocity space space equals space fraction numerator straight u plus straight v over denominator 2 end fraction
So space the space distance space covered space in space time space straight t space is space given space by comma

space straight s space equals space Average space velocity space cross times space Time space

space space space space equals space fraction numerator straight u plus straight v over denominator 2 end fraction cross times straight t
space space straight v plus straight u space equals space fraction numerator 2 straight s over denominator straight t end fraction space space space space space space space space... left parenthesis 1 right parenthesis
Now, using the first equation of motion:
     v = u + at  
rightwards double arrow  v - u = at      ... (2)
Multiplying equations (i) and (ii), we get
 left parenthesis straight v plus straight u right parenthesis thin space left parenthesis straight v minus straight u right parenthesis space equals space fraction numerator 2 straight s over denominator straight t end fraction cross times space at space space space space space space

rightwards double arrow space space space box enclose straight v squared minus straight u squared space equals space 2 as end enclose