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Matter In Our Surroundings

Question
CBSEENSC9005707

Usha swims in a 90 m pool. She covers 180 m in one minute by swimming from one end to the other and back along a straight path. Find the average speed and average velocity of Usha.

Solution

Total distance covered by Usha in 1 min = 180 m.
Displacement of Usha in 1 min = 0
Average space speed space equals space fraction numerator Total space distance space covered over denominator Total space time space taken end fraction

space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 180 space min over denominator 1 space min end fraction

space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 180 space straight m over denominator 60 space straight s end fraction space equals 3 space ms to the power of negative 1 end exponent

Average space velocity space equals space fraction numerator Displacement over denominator Total space time space taken end fraction space
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 0 over denominator 1 space min end fraction space equals space 0. space