The atomic numbers of aluminium and chlorine are 13 and 17 respectively. How many electrons are present in Al+3 and Cl- respectively?
Atomic no. of aluminium = 13
∴No. of protons in aluminium = 13
∴No. of electrons in aluminium = 13
Aluminium loses 3 electrons to give Al+3.
No. of electrons in Al+3 = 13 - 3 = 10
Thus,
Aluminium has 10 electron.
Similarly,
Atomic number of chlorine i=17
Chlorine gains one electron to give Cl-
No. of electrons in Cl- = 17 + 1 = 18.