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The Fundamental Unit Of Life

Question
CBSEENSC9005249

The atomic numbers of aluminium and chlorine are 13 and 17 respectively. How many electrons are present in Al+3 and Cl- respectively?

Solution

Atomic no. of aluminium = 13

∴No. of protons in aluminium = 13

∴No. of electrons in aluminium = 13
Aluminium loses 3 electrons to give Al+3.

No. of electrons in Al+3 = 13 - 3 = 10
Thus, 
Aluminium has 10 electron.

Similarly,

Atomic number of chlorine i=17
Chlorine gains one electron to give Cl-
No. of electrons in Cl- = 17 + 1 = 18.