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Three Dimensional Geometry

Question

If a vertex of a triangle is (1, 1) and the mid-points of two sides through this vertex are (-1, 2) and (3, 2), then the centroid of the triangle is

(-1, 7/3)

(-1/3, 7/3)

(1, 7/3)

(1/3, 7/3)

Solution

(1, 7/3)

Vertex of triangle is (1, 1) and midpoint of sides through this vertex is (-1, 2) and (3, 2) ⇒ vertex B and C come out to be (-3, 3) and (5, 3)
therefore centroid is $fraction numerator 1 minus 3 plus 5 over denominator 3 end fraction comma fraction numerator 1 plus 3 plus 3 over denominator 3 end fraction rightwards double arrow space left parenthesis 1 comma 7 divided by 3 right parenthesis$

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Three Dimensional Geometry

If a vertex of a triangle is (1, 1) and the mid-points of two sides through this vertex are (-1, 2) and (3, 2), then the centroid of the triangle is

(-1, 7/3)

(-1/3, 7/3)

(1, 7/3)

(1/3, 7/3)

Some More Questions From Three Dimensional Geometry Chapter

If α, β, γ are the angles which a line makes with the axes, prove that sin²α + sin² β + sin²γ = 2.

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

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For Daily Free Study Material Join wiredfaculty

Three Dimensional Geometry

If a vertex of a triangle is (1, 1) and the mid-points of two sides through this vertex are (-1, 2) and (3, 2), then the centroid of the triangle is (-1, 7/3) (-1/3, 7/3) (1, 7/3) (1/3, 7/3)

Some More Questions From Three Dimensional Geometry Chapter

If α, β, γ are the angles which a line makes with the axes, prove that sin2α + sin2 β + sin2γ = 2.

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

If a vertex of a triangle is (1, 1) and the mid-points of two sides through this vertex are (-1, 2) and (3, 2), then the centroid of the triangle is

(-1, 7/3)

(-1/3, 7/3)

(1, 7/3)

(1/3, 7/3)

If α, β, γ are the angles which a line makes with the axes, prove that sin²α + sin² β + sin²γ = 2.