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Vector Algebra

Question
CBSEENMA12036214

ABC is a triangle. Forces straight P with rightwards arrow on top comma space straight Q with rightwards arrow on top comma space straight R with rightwards arrow on top space acting along IA, IB and IC respectively are in equilibrium, where I is incentre of ∆ABC. Then P : Q : R is

  • sin A : sin B : sin C

  • sin space straight A over 2 space colon space Sin space straight B over 2 space colon space sin space straight C over 2
  • cos space straight A over 2 colon space cos space straight B over 2 space colon space Cos space straight C over 2
  • cosA : cosB : cosC

Solution

C.

cos space straight A over 2 colon space cos space straight B over 2 space colon space Cos space straight C over 2

Using Lami’s Theorem
therefore space straight P space colon space straight Q space colon straight R space equals space cos space straight A over 2 space colon space cos space straight B over 2 colon space cos straight C over 2