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Linear Programming

Question
CBSEENMA12036204
Wired Faculty App

If x is real, the maximum value of fraction numerator 3 straight x squared space plus 9 straight x space plus 17 over denominator 3 straight x squared space plus 9 straight x space plus 7 end fraction space is

  • 1/4

  • 41

  • 1

  • 17/7

Solution

B.

41

straight y space equals space fraction numerator 3 straight x squared space plus 9 straight x space plus 17 over denominator 3 straight x squared space plus 9 straight x space plus 7 end fraction 3 straight x squared space left parenthesis straight y minus 1 right parenthesis space plus 9 straight x left parenthesis straight y minus 1 right parenthesis space plus 7 straight y space minus 17 space equals space 0 straight D greater or equal than 0 space because space straight x space is space real 81 space left parenthesis straight y equals 1 right parenthesis squared space minus 4 straight x cubed left parenthesis straight y minus 1 right parenthesis left parenthesis 7 straight y minus 17 right parenthesis greater or equal than 0 rightwards double arrow space left parenthesis straight y minus 1 right parenthesis left parenthesis straight y minus 41 right parenthesis less or equal than 0 rightwards double arrow space 1 less or equal than space straight y less or equal than 41

Some More Questions From Linear Programming Chapter

Solve the following Linear Programming Problems graphically:
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Minimise and Maximise Z = 5x + 10y subject to constraints x + 2y ≤ 120,  x + y ≥ 60, x - 2 y ≥ 0, x, y ≥ 0.

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