A bag contains 4 red and 6 black balls. A ball is drawn at random from the bag, its colour is observed and this ball along with two additional balls of the same colour are returned to the bag. If now a ball is drawn at random from the bag, then the probability that this drawn ball is red, is:

3/4

3/10

2/5

1/5

Solution

2/5

E₁: Event that first ball drawn is red.
E₂: Event that first ball drawn is black.
E: Event that second ball drawn is red.

$P (E) = P (E_{1}) . P (\frac{E}{E_{1}}) + P (E_{2}) . P (\frac{E}{E_{2}}) = \frac{4}{10} x \frac{6}{12} + \frac{6}{10} x \frac{4}{12} = \frac{2}{5}$

For Daily Free Study Material Join wiredfaculty