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The value of ∫-π2π2sin2x1+2xdx is:
π/4
π/8
π/2
4π
A.
I = ∫-π2π2sin2 x dx1 + 2x ... (i)Also, I = ∫-π2π22x sin2 x dx1 + 2x .... (ii)Adding (i) and (ii)2I = ∫-π2π2 sin2 xdx2I = 2∫0π2sin2 x dx⇒ I = ∫0π2sin2 xdx .... (iii)I = ∫0π2cos2 xdx .... (iv)Adding (iii) and (iv)2I = ∫0π2dx = π2⇒I = π4
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