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Three Dimensional Geometry

Question
CBSEENMA12036287

If the curves y2 = 6x, 9x2 + by2 = 16 intersect each other at right angles, then the value of b is

  • 9/2

  • 6

  • 7/2

  • 4

Solution

A.

9/2

y2 = 6xm1 = - -62y = 3y= 9x2 + by2 = 16m2  = -18x2bym1m2 = -13y.-18y2by = -127xby2 = 1 y2x = 627b x 16 = 1b = 276 b = 92