Question
The intersection of the spheres x2 +y2 +z2 + 7x -2y-z =13 and x2 +y2 +z2 -3x +3y +4z = 8 is the same as the intersection of one of the sphere and the plane
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x-y-z =1
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x-2y-z =1
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x-y-2z=1
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2x-y-z =1
Solution
D.
2x-y-z =1
Required plane is S1 – S2 = 0 where
S1 = x2 + y2 + z2 + 7x – 2y – z – 13 = 0
and S2 = x2 + y2 + z2 – 3x + 3y + 4z – 8 = 0
⇒ 2x – y – z = 1.
