Question
Let A (2, –3) and B(–2, 1) be vertices of a triangle ABC. If the centroid of this triangle moves on the line 2x + 3y = 1, then the locus of the vertex C is the line
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2x + 3y = 9
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2x – 3y = 7
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3x + 2y = 5
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3x – 2y = 3
Solution
A.
2x + 3y = 9
If C be (h, k) then centroid is (h/3, (k – 2)/3) it lies on 2x + 3y = 1.
⇒ locus is 2x + 3y = 9.
