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Continuity And Differentiability

Question
CBSEENMA12036269
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The solution of the differential equation ydx + (x + x2y) dy = 0 is

  • -1/ XY  =C

  • -1/XY + log y = C

  • 1/XY + log y = C

  • log y =Cx

Solution

B.

-1/XY + log y = C

y dx + x dy + x2y dy = 0
fraction numerator straight d space left parenthesis xy right parenthesis over denominator straight x squared straight y squared end fraction space plus space 1 over straight y space dy space equals space 0 space rightwards double arrow space minus 1 over xy space plus space log space straight y space equals space straight C

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