The value of $integral subscript negative 2 end subscript superscript 3 space vertical line 1 minus straight x squared vertical line dx space is$

28/7

28/3

7/3

1/3

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Solution

28/3

integral subscript negative 2 end subscript superscript negative 1 end superscript space left parenthesis straight x squared minus 1 right parenthesis space dx space plus integral subscript negative 1 end subscript superscript 1 space left parenthesis 1 minus straight x squared right parenthesis space dx space plus integral subscript 1 superscript 3 left parenthesis straight x squared minus 1 right parenthesis space dx space equals space straight x cubed over 3 minus right enclose straight x subscript negative 2 end subscript superscript 1 space plus straight x minus right enclose straight x cubed over 3 end enclose subscript negative 1 end subscript superscript 1 plus straight x cubed over 3 minus right enclose right enclose straight x end enclose subscript 1 superscript 3 space equals space 28 over 3 space

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