Question
The lines p(p2+ 1) x – y + q = 0 and (p2+ 1)2x + (p2+ 1) y + 2q = 0 are
perpendicular to a common line for
-
no value of p
-
exactly one value of p
-
exactly two values of p
-
more than two values of p
Solution
B.
exactly one value of p
y = q
x + y + 2q = 0
⇒ p = –1
